35x^2-23x-72=0

Solution for 35x^2-23x-72=0 equation:

35x^2-23x-72=0

a = 35; b = -23; c = -72;
Δ = b2-4ac
Δ = -232-4·35·(-72)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-103}{2*35}=\frac{-80}{70}
=-1+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+103}{2*35}=\frac{126}{70}
=1+4/5
$